fix directives

Author: krother

challenges/binary_search.rst

@@ -8,7 +8,7 @@ A search problem
 
 Suppose you have a list of 1 million numbers:
 
-.. code:: python3
+.. code:: python
 
    from random import randint, seed
 
@@ -25,7 +25,7 @@ Brute-force solution
 
 Of course, you could loop through all the numbers:
 
-.. code:: python3
+.. code:: python
 
    def search(query, ids):
        """brute-force search"""
@@ -47,7 +47,7 @@ Recursive solution
 An alternative approach is **binary search**, one of the most
 fundamental recursive algorithms:
 
-.. code:: python3
+.. code:: python
 
    def binary_search(query, ids, start, stop):
        """recursive binary search"""
@@ -84,9 +84,9 @@ Challenge
 Measure the time it takes both algorithms to run on 1 million numbers.
 In IPython/Jupyter, you can use the magic function ``%time``:
 
-.. code:: ipython3
+.. code:: python
 
-   In [2]: %time search(8997173, ids)
+   %time search(8997173, ids)
 
 Compare the time required by the brute-force and binary implementations.
 Then increase the size of the data by factor 10 and repeat the

conf.py

@@ -23,7 +23,9 @@
     ]
 
 templates_path = ['_templates']
-exclude_patterns = ['_build', 'Thumbs.db', '.DS_Store', 'README.md']
+exclude_patterns = ['.venv', '.claude', 
+                    '_build', 'Thumbs.db',
+                    '.DS_Store', 'README.md']
 
 language = 'en'
 

performance/profiling.rst

@@ -15,7 +15,7 @@ Inspect the output and look for bottlenecks.
 
 Then insert the line:
 
-.. code:: python3
+.. code:: python
 
     z[index] = z[index] \*\* 2 + c[index]
 
@@ -25,7 +25,7 @@ Re-run the profiling.
 
    cProfile also works inside a program:
 
-   .. code:: python3
+   .. code:: python
 
        import cProfile
        cProfile.run("[x for x in range(1500)]")
@@ -35,13 +35,13 @@ Timing in Jupyter / IPython
 
 IPython (including Jupyter notebooks) has two magic commands for measuring execution time.
 
-.. code:: ipython3
+.. code:: python
 
     %time len(range(100000))
 
 compare the output to
 
-.. code:: ipython3
+.. code:: python
 
     %timeit